: a₁, a₂, a₃, ..., aₙ₋₄, aₙ₋₃, aₙ₋₂, aₙ₋₁, aₙ
📚 Understanding: What is meant by "the sum of the last 5 terms"?
❓ Conceptual question: Why is there no direct formula for the sum of the last k terms?
❓ Conceptual question: Why is there no direct formula for the sum of the last terms?
💡 Detailed explanation: Why no direct formula? ❓
The existing sum formula: Sₙ = a₁(qⁿ-1)/(q-1)The problem: This formula computes the sum from the beginning (from a₁) There is no direct formula starting from the middle!Solution: We need to compute: Total sum - sum of first terms = sum of last terms ⭐ This is the subtraction method!
➖ elimination method: 3 10 ?
💡 : elimination method! ➖
10 : a₁, a₂, ..., a₇, a₈, a₉, a₁₀
➖ Subtraction method: How do you find the sum of the last 3 terms of a sequence of 10 terms?
🔢 Calculation: Sequence: 2, 6, 18, 54, 162. What is the sum of the last 2 terms?
🔢 Computation: Sequence: 2, 6, 18, 54, 162 What is the sum of the last 2 terms?
💡 Detailed explanation: Computing the last 2 terms! 🔢
The sequence: a₁=2, a₂=6, a₃=18, a₄=54, a₅=162The last 2 terms: a₄ + a₅ = 54 + 162 = 216 Or by subtraction method: S₅ = 2+6+18+54+162 = 242 S₃ = 2+6+18 = 26 S₅ - S₃ = 242 - 26 = 216 ✓ ⭐ Both methods give the same result!
🔢 Using the formula: Geometric sequence: a₁=3, q=2, n=8 What is the sum of the last 3 terms?
💡 Detailed explanation: Using the sum formula! 🔢
Given: a₁ = 3, q = 2, n = 8Need: sum of last 3 = S₈ - S₅Compute S₈: S₈ = 3(2⁸-1)/(2-1) = 3×255 = 765Compute S₅: S₅ = 3(2⁵-1)/(2-1) = 3×31 = 93Sum of last 3: S₈ - S₅ = 765 - 93 = 576 ⭐ This equals a₆ + a₇ + a₈
🔢 Using the formula: Geometric sequence: a₁ = 3, q = 2, n = 8. What is the sum of the last 3 terms?
⚠️ Common error: A student wants to find the sum of the last 4 terms of a 12-term sequence. The student writes S₁₂ − S₄. What is wrong?
⚠️ Common mistake: A student wants to find the sum of the last 4 terms in a 12-term sequence. He computed S₁₂ - S₄ What is the mistake?
💡 Detailed explanation: The common mistake! ⚠️
❌ Wrong calculation: S₁₂ - S₄What does this give? It gives the sum of terms from a₅ to a₁₂ That is 8 terms! (not 4)✅ Correct calculation: Last 4 in a 12-term sequence: Need from a₉ to a₁₂ S₁₂ - S₈ = sum of last 4⭐ Rule: Last k terms = Sₙ - Sₙ₋ₖ Last 4 of 12 = S₁₂ - S₈
💡 : ! 📐
k n
📐 General formula: How do you find the sum of the last k terms of a sequence of n terms?
🔢 Exercise: a₁ = 1, q = 3, n = 10. What is the sum of the last 5 terms?
🔢 Exercise: a₁=1, q=3, n=10 Sum of the last 5 terms?
💡 Detailed explanation: Computing last 5 terms! 🔢
Need: S₁₀ - S₅Compute S₁₀: S₁₀ = 1×(3¹⁰-1)/(3-1) S₁₀ = (59,049-1)/2 S₁₀ = 59,048/2 = 29,524Compute S₅: S₅ = 1×(3⁵-1)/(3-1) S₅ = (243-1)/2 S₅ = 242/2 = 121Result: 29,524 - 121 = 14,640 This is a₆+a₇+a₈+a₉+a₁₀
🔢 : a₁=2, q=5, n=6 " " (1 )?
💡 : ! 🔢
1: a₆ = a₁ × q⁵ a₆ = 2 × 5⁵ a₆ = 2 × 3,125 a₆ = 6,250 2: elimination method S₆ - S₅ S₆ = 2(5⁶-1)/4 = 2×3,906 = 7,812 S₅ = 2(5⁵-1)/4 = 2×781 = 1,562 7,812 - 1,562 = 6,250 ✓ ⭐ No !
🔢 Special case: a₁ = 2, q = 5, n = 6. What is the "sum of the last term only" (1 term)?
🔢 Exercise: a₁ = 5, q = 2, n = 7. What is the sum of the last 2 terms?
🔢 Exercise: a₁=5, q=2, n=7 Sum of the last 2 terms?
💡 Detailed explanation: Last 2 terms! 🔢
Need: S₇ - S₅Compute S₇: S₇ = 5(2⁷-1)/(2-1) S₇ = 5×127 = 635Compute S₅: S₅ = 5(2⁵-1)/(2-1) S₅ = 5×31 = 155Result: 635 - 155 = 480 Direct check: a₆ = 5×2⁵ = 160 a₇ = 5×2⁶ = 320 160 + 320 = 480 ✓
🔢 Exercise: a₁=4, q=3, n=9 Sum of the last 4 terms?
💡 Detailed explanation: Last 4 terms! 🔢
Need: S₉ - S₅Compute S₉: S₉ = 4(3⁹-1)/(3-1) S₉ = 4×(19,683-1)/2 S₉ = 4×9,841 = 39,364Compute S₅: S₅ = 4(3⁵-1)/(3-1) S₅ = 4×(243-1)/2 S₅ = 4×121 = 484Last 4: S₉ - S₅ = 39,364 - 484 = 26,244 This is a₆ + a₇ + a₈ + a₉
🔢 Exercise: a₁ = 4, q = 3, n = 9. What is the sum of the last 4 terms?
🔢 Decimal ratio: a₁ = 100, q = 0.5, n = 8. What is the sum of the last 3 terms?
🔢 Decimal ratio: a₁=100, q=0.5, n=8 Sum of the last 3 terms?
💡 Detailed explanation: Ratio less than 1! 🔢
Need: S₈ - S₅Compute S₈: S₈ = 100(1-0.5⁸)/(1-0.5) S₈ = 100×(1-0.00390625)/0.5 S₈ = 100×1.9921875 = 199.21875Compute S₅: S₅ = 100(1-0.5⁵)/(1-0.5) S₅ = 100×(1-0.03125)/0.5 S₅ = 100×1.9375 = 193.75Last 3: 199.21875 - 193.75 = 4.6875 ⭐ When q<1 the sequence decreases!
🔍 : a₁=2, q=3, n=8 4,920 ?
💡 : ! 🔍
given: S₈ - Sₖ = 4,920 S₈: S₈ = 2(3⁸-1)/(3-1) S₈ = 2×3,280 = 6,560Yes: 6,560 - Sₖ = 4,920 Sₖ = 6,560 - 4,920 = 1,640 k: 1,640 = 2(3ᵏ-1)/2 1,640 = 3ᵏ - 1 3ᵏ = 1,641 : 3⁴ = 81 ✗, 3⁵ = 243 ✗ ! : 3⁴ = 81, Yes... : k=4, because S₄ = 2×40 = 80.
🔍 Reverse problem: a₁ = 2, q = 3, n = 8. The sum of the last k terms is 4,920. How many terms are included?
📊 Half the sequence: In a sequence of 10 terms: a₁ = 3, q = 2. What is the sum of the last 5 terms?
📊 Half the sequence: In a 10-term sequence: a₁=3, q=2 Sum of the last 5 terms?
💡 Detailed explanation: Last half! 📊
Need: S₁₀ - S₅Compute S₁₀: S₁₀ = 3(2¹⁰-1)/(2-1) S₁₀ = 3×1,023 = 3,069Compute S₅: S₅ = 3(2⁵-1)/(2-1) S₅ = 3×31 = 93Last half: 3,069 - 93 = 3,024 ⭐ The last half is much larger! (because q>1)
⚖️ : : a₁=1, q=2, n=10 large : 5 5 ?
💡 : ! ⚖️
5
⚖️ Comparison: Sequence: a₁ = 1, q = 2, n = 10. Which is larger: the sum of the first 5 or the last 5 terms?
🔢 Exercise: a₁ = 1, q = 4, n = 8. What is the sum of the last 6 terms?
🔢 Exercise: a₁=1, q=4, n=8 Sum of the last 6 terms?
💡 Detailed explanation: Last 6 terms! 🔢
Need: S₈ - S₂Compute S₈: S₈ = 1×(4⁸-1)/(4-1) S₈ = (65,536-1)/3 S₈ = 65,535/3 = 21,845Compute S₂: S₂ = 1×(4²-1)/(4-1) S₂ = 15/3 = 5Last 6: 21,845 - 5 = 21,840 This is a₃ + a₄ + a₅ + a₆ + a₇ + a₈
💡 : ! 🤔
a₁, a₂, a₃, a₄, a₅, a₆, a₇, a₈, a₉, a₁₀, a₁₁, a₁₂, a₁₃, a₁₄, a₁₅
🤔 Understanding: In a sequence of 15 terms, we calculated S₁₅ − S₁₀. What does this represent?
🔢 Exercise: a₁ = 2, q = 2, n = 12. What is the sum of the last 7 terms?
🔢 Exercise: a₁=2, q=2, n=12 Sum of the last 7 terms?
💡 Detailed explanation: Last 7 terms! 🔢
Need: S₁₂ - S₅Compute S₁₂: S₁₂ = 2(2¹²-1)/(2-1) S₁₂ = 2×4,095 = 8,190Compute S₅: S₅ = 2(2⁵-1)/(2-1) S₅ = 2×31 = 62Last 7: 8,190 - 62 = 8,128 This is a₆ + a₇ + a₈ + a₉ + a₁₀ + a₁₁ + a₁₂
💰 Application: You deposited $1,000 in the bank. Each year the money is multiplied by 1.1 After 10 years, how much did you earn in the last 3 years?
💡 Detailed explanation: Earnings in the last years! 💰
Setup: a₁ = 1,000 q = 1.1 n = 10Need: sum of last 3 = S₁₀ - S₇Compute S₁₀: S₁₀ = 1,000(1.1¹⁰-1)/(1.1-1) S₁₀ = 1,000×(2.5937-1)/0.1 S₁₀ ≈ 15,937Compute S₇: S₇ = 1,000(1.1⁷-1)/0.1 S₇ ≈ 9,487Last 3: 15,937 - 9,487 ≈ 6,450 Note: the actual gain is the difference from principal, so a different calculation is needed.
💰 Application: 1,000 was deposited in a bank. Each year the amount is multiplied by 1.1. After 10 years, what is the sum of the last 3 years?
📋 Summary: What is the core principle for finding the sum of the last terms?
💡 : ! 📋
💡 : ! 📐
a₁ + a₂ + a₃ + ... + aₙ₋₁ + aₙ
📐 Principle: How do you find aₙ from the formula Sₙ?
❓ Question: Why does the formula aₙ = Sₙ − Sₙ₋₁ work only for n ≥ 2?
❓ Question: Why does the formula aₙ = Sₙ - Sₙ₋₁ work only for n≥2?
💡 Detailed explanation: Why only n≥2? ❓
What happens when n=1? By the formula: a₁ = S₁ - S₀The problem: S₀ = sum of 0 terms? This is not defined! The solution: a₁ has a special rule:a₁ = S₁ For all the rest (n≥2): aₙ = Sₙ - Sₙ₋₁ ⭐ Two rules: one for a₁, one for the rest!
🔢 Example: Given: Sₙ = 3n² + 2n What is a₁?
💡 Detailed explanation: Finding a₁! 🔢
Given: Sₙ = 3n² + 2nSpecial rule for a₁: a₁ = S₁Computation: a₁ = S₁ = 3×1² + 2×1 a₁ = 3×1 + 2 a₁ = 3 + 2 a₁ = 5 Check: S₁ should equal a₁ alone S₁ = 5 ✓
🔢 Example: Given: Sₙ = 3n² + 2n. What is a₁?
🔢 Example: Given: Sₙ = 3n² + 2n. What is a₂?
🔢 Example: Given: Sₙ = 3n² + 2n What is a₂?
💡 Detailed explanation: Finding a₂! 🔢
Given: Sₙ = 3n² + 2nFormula: a₂ = S₂ - S₁Compute S₂: S₂ = 3×2² + 2×2 S₂ = 3×4 + 4 S₂ = 12 + 4 = 16Compute S₁: S₁ = 3×1² + 2×1 = 5 (this is a₁ found earlier)Therefore: a₂ = 16 - 5 = 11 Check: a₁ + a₂ = 5 + 11 = 16 = S₂ ✓
🔢 Example: Given: Sₙ = 3n² + 2n What is a₃?
💡 Detailed explanation: Finding a₃! 🔢
Formula: a₃ = S₃ - S₂Compute S₃: S₃ = 3×3² + 2×3 S₃ = 3×9 + 6 S₃ = 27 + 6 = 33Compute S₂: S₂ = 16 (computed earlier)Therefore: a₃ = 33 - 16 = 17 The sequence so far: a₁ = 5, a₂ = 11, a₃ = 17 ⭐ See the pattern? It is an arithmetic sequence! d=6
🔢 Example: Given: Sₙ = 3n² + 2n. What is a₃?
📐 General formula: Given: Sₙ = 3n² + 2n. What is the general formula for aₙ (for n ≥ 2)?
📐 General formula: Given: Sₙ = 3n² + 2n What is the general term formula aₙ (for n≥2)?
💡 Detailed explanation: Deriving the term formula! 📐
Given: Sₙ = 3n² + 2nComputation: aₙ = Sₙ - Sₙ₋₁ Sₙ = 3n² + 2n Sₙ₋₁ = 3(n-1)² + 2(n-1) Sₙ₋₁ = 3(n² - 2n + 1) + 2n - 2 Sₙ₋₁ = 3n² - 6n + 3 + 2n - 2 Sₙ₋₁ = 3n² - 4n + 1Subtraction: aₙ = (3n² + 2n) - (3n² - 4n + 1) aₙ = 3n² + 2n - 3n² + 4n - 1 aₙ = 6n - 1 Check: a₂ = 6×2 - 1 = 11 ✓ a₃ = 6×3 - 1 = 17 ✓
✅ Verification: We found: aₙ = 6n - 1 a₁ = 5 Does the formula also work for a₁?
💡 Detailed explanation: Checking the formula! ✅
The formula we found: aₙ = 6n - 1 (for n≥2)Check for n=1: a₁ = 6×1 - 1 = 5What we computed from S₁: a₁ = S₁ = 5Result: 5 = 5 ✓Conclusion: In this case the formula also works for a₁! So we can write: aₙ = 6n - 1 for all n≥1 ⭐ This does not always happen - always check!
✅ Check: We found: aₙ = 6n − 1, a₁ = 5. Does the formula work for a₁?
🔢 New example: Given: Sₙ = 2ⁿ − 1. What is a₁?
🔢 New example: Given: Sₙ = 2ⁿ - 1 What is a₁?
💡 Detailed explanation: Finding a₁! 🔢
Given: Sₙ = 2ⁿ - 1Rule: a₁ = S₁Computation: a₁ = S₁ = 2¹ - 1 a₁ = 2 - 1 a₁ = 1 Insight: This is the sum formula of a geometric sequence! a₁=1, q=2 ⭐ Recognize the formula: Sₙ = a₁(qⁿ-1)/(q-1)
🔢 Continued: Given: Sₙ = 2ⁿ - 1 What is a₂?
💡 Detailed explanation: Finding a₂! 🔢
Formula: a₂ = S₂ - S₁Compute S₂: S₂ = 2² - 1 S₂ = 4 - 1 = 3Compute S₁: S₁ = 1 (found earlier)Therefore: a₂ = 3 - 1 = 2 The sequence: a₁ = 1, a₂ = 2 The ratio: q = a₂/a₁ = 2/1 = 2 ✓ ⭐ This is a geometric sequence with q=2!
🔢 Continued: Given: Sₙ = 2ⁿ − 1. What is a₂?
📐 General formula: Given: Sₙ = 2ⁿ − 1. What is the general formula for aₙ?
📐 General formula: Given: Sₙ = 2ⁿ - 1 What is the general term formula aₙ?
💡 Detailed explanation: Deriving the formula! 📐
Computation: aₙ = Sₙ - Sₙ₋₁ Sₙ = 2ⁿ - 1 Sₙ₋₁ = 2ⁿ⁻¹ - 1Subtraction: aₙ = (2ⁿ - 1) - (2ⁿ⁻¹ - 1) aₙ = 2ⁿ - 1 - 2ⁿ⁻¹ + 1 aₙ = 2ⁿ - 2ⁿ⁻¹ aₙ = 2ⁿ⁻¹(2 - 1) aₙ = 2ⁿ⁻¹ Check: a₁ = 2⁰ = 1 ✓ a₂ = 2¹ = 2 ✓ a₃ = 2² = 4 ⭐ This is exactly the geometric sequence formula: aₙ = a₁ × qⁿ⁻¹
🔢 New example: Given: Sₙ = n² + n What is a₁?
💡 Detailed explanation: Finding a₁! 🔢
Given: Sₙ = n² + nComputation: a₁ = S₁ a₁ = 1² + 1 a₁ = 1 + 1 a₁ = 2 We can factor: Sₙ = n² + n = n(n + 1) Therefore: S₁ = 1(1 + 1) = 2 ✓
🔢 New example: Given: Sₙ = n² + n. What is a₁?
📐 Formula: Given: Sₙ = n² + n. What is the formula for aₙ (for n ≥ 2)?
📐 Formula: Given: Sₙ = n² + n What is the general term formula aₙ (for n≥2)?
💡 Detailed explanation: Deriving the formula! 📐
Computation: aₙ = Sₙ - Sₙ₋₁ Sₙ = n² + n Sₙ₋₁ = (n-1)² + (n-1) Sₙ₋₁ = n² - 2n + 1 + n - 1 Sₙ₋₁ = n² - nSubtraction: aₙ = (n² + n) - (n² - n) aₙ = n² + n - n² + n aₙ = 2n Check: a₂ = 2×2 = 4 S₂ = 2² + 2 = 6 = a₁ + a₂ = 2 + 4 ✓ ⭐ This is an arithmetic sequence! d=2
⚠️ Verification: We found: aₙ = 2n, a₁ = 2 Does the formula work for a₁?
💡 Detailed explanation: Verification! ⚠️
The formula: aₙ = 2nCheck for n=1: a₁ = 2×1 = 2Direct computation from S₁: a₁ = S₁ = 1² + 1 = 2Result: 2 = 2 ✓Conclusion: In this case the formula also works for a₁! So: aₙ = 2n for all n≥1 The sequence: 2, 4, 6, 8, 10... ⭐ Even numbers!
⚠️ Check: We found: aₙ = 2n, a₁ = 2. Does the formula work for a₁?
🔢 Example: Given: Sₙ = n² + 2n + 1. What is a₁?
🔢 Example: Given: Sₙ = n² + 2n + 1 What is a₁?
💡 Detailed explanation: Finding a₁! 🔢
Given: Sₙ = n² + 2n + 1Computation: a₁ = S₁ a₁ = 1² + 2×1 + 1 a₁ = 1 + 2 + 1 a₁ = 4 Note: We can see that: Sₙ = n² + 2n + 1 = (n + 1)² Therefore: S₁ = (1 + 1)² = 2² = 4 ✓
📐 Formula: Given: Sₙ = n² + 2n + 1 What is the formula for aₙ (for n≥2)?
💡 Detailed explanation: Derivation! 📐
Computation: Sₙ = n² + 2n + 1 Sₙ₋₁ = (n-1)² + 2(n-1) + 1 Sₙ₋₁ = n² - 2n + 1 + 2n - 2 + 1 Sₙ₋₁ = n² + 0n + 0 = n²Subtraction: aₙ = (n² + 2n + 1) - n² aₙ = 2n + 1 Check for a₁: a₁ = 2×1 + 1 = 3 But we computed a₁ = 4 ✗Conclusion: The formula aₙ = 2n + 1 works only for n≥2 a₁ has a special value: a₁ = 4 ⭐ The sequence: 4, 5, 7, 9, 11...
📐 Formula: Given: Sₙ = n² + 2n + 1. What is the formula for aₙ (for n ≥ 2)?
🔢 Application: Given: Sₙ = 2n² − n. What is a₅?
🔢 [MATH_FLAG] Application: Given: Sₙ = 2n² - n What is a₅?Note: source contains a calculation error in the explanation; please verify the marked answer.
💡 Detailed explanation: Finding a₅! [MATH_FLAG] 🔢
Formula: a₅ = S₅ - S₄Compute S₅: S₅ = 2×5² - 5 S₅ = 2×25 - 5 S₅ = 50 - 5 = 45Compute S₄: S₄ = 2×4² - 4 S₄ = 2×16 - 4 S₄ = 32 - 4 = 28Therefore: a₅ = 45 - 30 = 15 ⚠ Note: there is a calculation discrepancy. The arithmetic 45 - 28 = 17, not 15. The source explanation acknowledges: "Wait, calculation error: a₅ = 45 - 28 = 17... oops! Need to fix the answer." Please review and correct.
📐 Exercise: Given: Sₙ = n³ What is the formula for aₙ (for n≥2)?
💡 Detailed explanation: Derivation! 📐
Computation: Sₙ = n³ Sₙ₋₁ = (n-1)³Expand: (n-1)³ = n³ - 3n² + 3n - 1Subtraction: aₙ = n³ - (n³ - 3n² + 3n - 1) aₙ = n³ - n³ + 3n² - 3n + 1 aₙ = 3n² - 3n + 1 Check: a₁ = S₁ = 1³ = 1 By the formula: a₁ = 3×1 - 3×1 + 1 = 1 ✓ a₂ = S₂ - S₁ = 8 - 1 = 7 By the formula: a₂ = 3×4 - 6 + 1 = 7 ✓ ⭐ The formula works for all n≥1!
📐 Exercise: Given: Sₙ = n³. What is the formula for aₙ (for n ≥ 2)?
🔍 Identification: Given: Sₙ = 5n. What kind of sequence is this?
🔍 Identification: Given: Sₙ = 5n What kind of sequence is this?
💡 Detailed explanation: Identifying the sequence! 🔍
Given: Sₙ = 5nFinding a₁: a₁ = S₁ = 5×1 = 5Finding aₙ: aₙ = Sₙ - Sₙ₋₁ aₙ = 5n - 5(n-1) aₙ = 5n - 5n + 5 aₙ = 5The sequence: 5, 5, 5, 5, 5, 5...Conclusion: This is a constant sequence! All terms equal 5 ⭐ Can be viewed as: • Arithmetic with d=0 • Geometric with q=1
🔢 Exercise: Given: Sₙ = 3ⁿ - 2 What is a₃?
💡 Detailed explanation: Computing a₃! 🔢
Formula: a₃ = S₃ - S₂Compute S₃: S₃ = 3³ - 2 S₃ = 27 - 2 = 25Compute S₂: S₂ = 3² - 2 S₂ = 9 - 2 = 7Therefore: a₃ = 25 - 7 = 18 The sequence: a₁ = S₁ = 3 - 2 = 1 a₂ = S₂ - S₁ = 7 - 1 = 6 a₃ = 18 The ratio: 6/1 = 6, 18/6 = 3... not geometric! ⭐ But aₙ = 3ⁿ - 3ⁿ⁻¹ = 3ⁿ⁻¹(3-1) = 2×3ⁿ⁻¹
🔢 Exercise: Given: Sₙ = 3ⁿ − 2. What is a₃?
📋 Summary: What are the steps for finding aₙ from Sₙ?