Practice Z-Scores — Interpretation and Comparison
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📖 Statistics – Z-Score: Interpretation, Calculation and Comparison
Imagine: Danny scored 80 in maths and 80 in English.
Are these the same achievement in both subjects?
Not necessarily! If the Maths mean was 70 and English 85, then 80 in Maths is above average, but 80 in English is below average.!
The Z-score solves exactly this problem — it translates every score into a "common language" that allows fair comparison.
What Is a Z-Score?
A Z-score measures how far a value is from the mean, where distance is measured in units of standard deviation — not in points.
A Z-score does not say "how many points you have" — it says "where you stand relative to everyone else"..
Formula
\(z = \dfrac{x - \bar{x}}{S}\)
Where:
- \(x\) = individual value (e.g. a student's score)
- \(\bar{x}\) = group mean
- \(S\) = group standard deviation
How to Interpret a Z-Score?
| Z-score | Meaning | Example |
|---|---|---|
| \(z > 0\) | Value above the mean | \(z = 1.5\) → 1.5 SDs above mean |
| \(z = 0\) | Value equal to the mean | Your score is exactly at the mean |
| \(z < 0\) | Value below the mean | \(z = -2\) → 2 SDs below mean |
Example 1 — Basic Z-Score Calculation
For a certain class:
- Mean: \(\bar{x} = 70\)
- SD: \(S = 10\)
- Dana scored: \(x = 85\)
\(z = \dfrac{x - \bar{x}}{S} = \dfrac{85 - 70}{10}\)
🔢 Step 2 — Calculate the numerator:\(85 - 70 = 15\)
🔢 Step 3 — Divide by the standard deviation:\(z = \dfrac{15}{10} = 1.5\)
Example 2 — Negative Z-Score
In the same class (\(\bar{x} = 70\), \(S = 10\)), Yossi scored: \(x = 55\)
\(z = \dfrac{55 - 70}{10} = \dfrac{-15}{10} = -1.5\)
Example 3 — Z-Score of Zero
In the same class (\(\bar{x} = 70\), \(S = 10\)), Michal scored: \(x = 70\)
\(z = \dfrac{70 - 70}{10} = \dfrac{0}{10} = 0\)
🎯 Comparing Across Different Groups
Here is the real power of Z-scores! They allow comparison of performance even when means and standard deviations differ..
Danny scored 80 in Maths and80 in English. In which subject is he better relative to the class??
| Maths | English | |
|---|---|---|
| Danny's score | 80 | 80 |
| Class mean | \(\bar{x} = 70\) | \(\bar{x} = 70\) |
| SD | \(S = 10\) | \(S = 5\) |
\(z_{\text{מתמ}} = \dfrac{80 - 70}{10} = \dfrac{10}{10} = 1\)
Z-score calculation — English:\(z_{\text{אנג}} = \dfrac{80 - 70}{5} = \dfrac{10}{5} = 2\)
Although Danny scored the same raw mark (80), he performs better in English relative to the class because he is further from the mean (2 SDs vs only 1).
In English the SD is small (\(S = 5\)), meaning most students cluster near the mean. Scoring 10 points above the mean in a tight group is a bigger achievement than the same gap in a spread-out group..
Common Mistakes
| ❌ Mistake | ✅ Correct |
|---|---|
| "\(z = 0\) means the score is zero" | \(z = 0\) means the score equals the mean, not that it is zero! |
| "\(z = -1.5\) means the score is negative" | \(z\) Negative Z means below average.below the mean, not that the raw score is negative |
| Danny scored 80 in both, so he is at the same level | Need to compare Z-scores, not raw scores |
| Z-score is measured in points | Z-scores are measured in units of standard deviation |
Summary — When to Use Z-Scores?
- ✅ To know where a value sts relative to the rest
- ✅ To compare across different groups (subjects, classes, tests)
- ✅ To identify outliers
- ✅ To work with the normal distribution and Z-table
Worked Examples
📑 – :
distribution normal ( Z), \(P(Z > 0)\) ?
Show solution
normal (μ=0, σ=1) 0. Yes area find -0 .
:
P(Z > 0) = 0.5.
📑 : P(Z > 1.0)
, \(P(Z > 1.0)\) ?
Show solution
No Z P(Z > z) (area ). z=1.0 0 0.1587.
probability large mean 15.87%.
📑 : P(Z > 1.5)
\(P(Z > 1.5)\) ?
Show solution
: z = 1.5, area 0.0668, -6.7% area.
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