Geometry Theorems — Thales' Theorem and Triangle Similarity

Geometry Theorems — Thales' Theorem and Triangle Similarity. Practice questions to deepen understanding of Thales' theorem and triangle similarity. Online math practice with full solutions and step-by-step explanations.

Thales' theorem and similarity practice — Thales, equal ratios, similarity theorems AA/SSS/SAS, similarity ratio, ratio of areas.

Thales' theorem: parallel lines → equal ratios. Thales in a triangle: DE ∥ third side.

20 questions

Question 1
5.00 pts

Thales theorem:

If three parallel lines intersect two transversals, then:

Explanation:
⫽ The basic Thales theorem

Thales theorem:

If three parallel lines intersect two transversals,

then the ratios between the segments are equal!

AB/BC = DE/EF ✓

ABBCDEEFAB/BC = DE/EF
Question 2
5.00 pts

Thales in a triangle:

If a line is parallel to a side in a triangle, then:

Explanation:
△ Thales theorem in a triangle

Theorem:

If DE ∥ BC in triangle ABC,

then: AD/DB = AE/EC

The parallel line divides the sides in the same ratio!

DEADDBAEECAD/DB = AE/EC
Question 3
5.00 pts

↔️ Converse theorem:

If a line divides two sides of a triangle in the same ratio, then:

Explanation:
↔️ The converse theorem

Converse theorem:

If in triangle ABC:

AD/DB = AE/EC

then DE ∥ BC

This is a way to prove parallelism!

Summary:

DE ∥ BC ⇔ AD/DB = AE/EC

(both directions are true!)
Question 4
5.00 pts

Definition:

Two triangles are similar if:

Explanation:
△ Triangle similarity

Definition:

Two triangles are similar if:

1. All corresponding angles are equal
2. The ratio of corresponding sides is constant

Notation: △ABC ~ △DEF

smalllarge~same shape!
Question 5
5.00 pts

📐 Similarity ratio:

In similar triangles with similarity ratio k=2, the ratio of perimeters is:

Explanation:
📐 Similarity ratio

Rule:

If the similarity ratio = k

then:

• Ratio of lengths (sides, perimeter) = k
• Ratio of areas =
• Ratio of volumes =

In our case:

k = 2

Ratio of perimeters = 2:1 ✓
Ratio of areas = 4:1
Question 6
5.00 pts

AAA similarity:

Two triangles are similar if:

Explanation:
∠ AAA similarity theorem (AA)

Theorem:

If three corresponding angles are equal,

then the triangles are similar! ✓

∠A = ∠D, ∠B = ∠E, ∠C = ∠F

⇒ △ABC ~ △DEF

In fact, two are enough:

Two equal angles (AA)!

The third follows from the 180° sum ✓
Question 7
5.00 pts

SSS similarity:

Two triangles are similar if:

Explanation:
━ SSS similarity theorem

Theorem:

If the ratio of three corresponding sides is constant,

then the triangles are similar! ✓

AB/DE = BC/EF = AC/DF = k

⇒ △ABC ~ △DEF

Example:

The 3-4-5 triangle is similar to the 6-8-10 triangle

Ratio: 3/6 = 4/8 = 5/10 = 1/2 ✓
Question 8
5.00 pts

SAS similarity:

Two triangles are similar if:

Explanation:
∠ SAS similarity theorem

Theorem:

If two sides have the same ratio and the included angle between them is equal,

then the triangles are similar! ✓

AB/DE = AC/DF and ∠A = ∠D

⇒ △ABC ~ △DEF

⚠️ Important:

The angle must be included (between the two sides)!
Question 9
5.00 pts

🔢 Computation:

In a triangle, DE ∥ BC. If AD=4, DB=2, AE=6, then EC equals:

Explanation:
🔢 Application of Thales theorem

Given:

DE ∥ BC
AD = 4, DB = 2
AE = 6, EC = ?

Solution:

Thales theorem:

AD/DB = AE/EC

4/2 = 6/EC

2 = 6/EC

EC = 3 ✓
Question 10
5.00 pts

🔢 Computation:

Two similar triangles with sides 3-4-5 and 6-8-10. The similarity ratio is:

Explanation:
🔢 Finding the similarity ratio

Given:

Triangle 1: 3-4-5
Triangle 2: 6-8-10

Solution:

Ratio = small side / large side

3/6 = 4/8 = 5/10 = 1/2 ✓

Similarity ratio: 1:2
Question 11
5.00 pts

📐 Areas:

In similar triangles with similarity ratio 3:1, the ratio of areas is:

Explanation:
📐 Ratio of areas

Rule:

If the similarity ratio = k

then the ratio of areas =

In our case:

Similarity ratio = 3:1

k = 3

Ratio of areas = 3² : 1² = 9:1 ✓
Question 12
5.00 pts

Angle bisector:

The angle bisector in a triangle divides the opposite side in the ratio of:

Explanation:
∠ Angle bisector theorem

Theorem:

The angle bisector divides the opposite side in the ratio of the sides!

If AD bisects ∠A,

then BD/DC = AB/AC ✓

This is an extension of Thales theorem!

ABACBDDCBD/DC = AB/AC
Question 13
5.00 pts

📏 Heights:

In similar triangles with similarity ratio k, the ratio of heights is:

Explanation:
📏 Ratio of heights

Rule:

In similar triangles:

The ratio of all lengths (sides, heights, medians, radii) = k

Everything in the same ratio!

Example:

If similarity ratio = 2:1

then:
• Ratio of heights = 2:1
• Ratio of medians = 2:1
• Ratio of perimeters = 2:1
Question 14
5.00 pts

Right triangle:

The altitude to the hypotenuse in a right triangle creates:

Explanation:
⊿ Similarity in right triangle

Important theorem:

The altitude to the hypotenuse in a right triangle divides it into two triangles

And all three (the original + the 2 smaller ones) are similar to each other! ✓

~~
Triple similarity:

△ABC ~ △ACD ~ △CBD ✓
Question 15
5.00 pts

🔍 Identification:

A triangle with angles 50°-60°-70° is similar to a triangle with angles:

Explanation:
🔍 Identifying similarity

Rule:

Triangles are similar if all angles are equal!

50°-60°-70° is similar only to 50°-60°-70° ✓

⚠️ Common error:

Is 25°-30°-35° half of 50°-60°-70°?

No! Angles do not work in ratios!

The exact same angles are needed ✗

(Also: 25°+30°+35° = 90° ≠ 180°!)
Question 16
5.00 pts

🔢 Computation:

A large triangle is similar to a small triangle in ratio 4:1. If the area of the small one is 5 cm², the area of the large one is:

Explanation:
🔢 Area computation

Given:

Similarity ratio = 4:1
Small area = 5 cm²
Large area = ?

Solution:

Ratio of areas = (similarity ratio)²

Ratio of areas = 4² : 1² = 16:1

Large area = 5 × 16 = 80 cm² ✓
Question 17
5.00 pts

Extended Thales:

A line parallel to one of the triangle sides and passing through the midpoint of a second side:

Explanation:
⫽ Extended Thales - midsegment

Theorem:

If a line is parallel to a triangle side and passes through the midpoint of a second side,

then it passes through the midpoint of the third side! ✓

This is a midsegment!

Explanation:

By Thales: AD/DB = AE/EC

If AD = DB (midpoint),

then also AE = EC (midpoint) ✓
Question 18
5.00 pts

Relationship:

Congruent triangles are also:

Explanation:
△ Congruence and similarity

Relationship:

Congruence = a special case of similarity!

Congruence ⊂ similarity ✓

Congruent triangles = similar with ratio 1:1

Difference:

• Congruence: same shape and same size
• Similarity: same shape (different sizes allowed)
Question 19
5.00 pts

🔢 Application:

In a right triangle with legs 6 and 8, the altitude to the hypotenuse equals:

Explanation:
🔢 Altitude to hypotenuse via similarity

Solution 1 - via area:

Hypotenuse: c = √(6²+8²) = 10

Area: S = ½×6×8 = 24

Also: S = ½×c×h = ½×10×h

24 = 5h

h = 4.8 ✓

Solution 2 - formula:

h = (a×b)/c = (6×8)/10 = 48/10 = 4.8 ✓
Question 20
5.00 pts

📚 Summary:

Which of the following theorems is not true?

Explanation:
📚 Similarity summary

The false claim:

"In similar triangles the ratio of angles is constant"

This is false!

Angles are not in a ratio - they are exactly equal!

∠A = ∠D (not in ratio) ⚠️

The correct theorems:

✓ All corresponding angles are equal (not in ratio!)
✓ Ratio of corresponding sides is constant = k
✓ Ratio of lengths = k
✓ Ratio of areas = k²
✓ Ratio of volumes = k³
✓ Thales theorem: line ∥ to side ⇒ same ratio division
✓ Similarity theorems: AA, SSS, SAS
✓ Angle bisector: BD/DC = AB/AC
✓ Congruence = similarity with k=1