Normal Distribution – Raw Score to Probability | G11

Normal Distribution

From Raw Score to Probability – The Full Process

🎯 The Full Process

Raw score (x)

Z-score (Z)

Probability/percentage

Step 1: Compute the Z-score: \(Z = \frac{x - \bar{x}}{S}\)

Step 2: Look up the probability in the Z-table

Step 3: Adjust if needed (complement, subtract areas)

✏️ Example 1: P(X < a) – less than a value

Question: Test scores are normally distributed with mean 75 and SD 10.

What is the probability that a student scores below 85?

Step 1 – Computing Z:

\(Z = \frac{85 - 75}{10} = \frac{10}{10} = 1\)

Step 2 – Reading the table:

P(Z ≤ 1) = 0.8413

Answer: 84.13% of students score below 85

✏️ Example 2: P(X > a) – greater than a value

Question: Women's height is normally distributed with mean 165 cm and SD 6 cm.

What is the probability that a woman is taller than 175 cm?

Step 1 – Computing Z:

\(Z = \frac{175 - 165}{6} = \frac{10}{6} \approx 1.67\)

Step 2 – Reading the table:

P(Z ≤ 1.67) = 0.9525

Step 3 – Complementary (because we ask "greater than"):

P(Z > 1.67) = 1 - 0.9525 = 0.0475

Answer: 4.75% of women are taller than 175 cm

✏️ Example 3: P(a < X < b) – between two values

Question: Baby weight is normally distributed with mean 3.2 kg and SD 0.5 kg.

What is the probability that a baby weighs between 2.8 and 3.5 kg?

Step 1 – Computing Z for both values:

\(Z_1 = \frac{2.8 - 3.2}{0.5} = \frac{-0.4}{0.5} = -0.8\)

\(Z_2 = \frac{3.5 - 3.2}{0.5} = \frac{0.3}{0.5} = 0.6\)

Step 2 – Reading the table:

P(Z ≤ -0.8) = 0.2119

P(Z ≤ 0.6) = 0.7257

Step 3 – Subtracting areas:

P(-0.8 < Z < 0.6) = 0.7257 - 0.2119 = 0.5138

Answer: 51.38% of babies weigh between 2.8 and 3.5 kg

✏️ Example 4: Symmetric area about the mean

Question: IQ scores are normally distributed with mean 100 and SD 15.

What is the probability that a person has an IQ between 85 and 115?

💡 Note: The range is symmetric about the mean! (100±15)

Step 1 – Computing Z:

\(Z_1 = \frac{85 - 100}{15} = -1\)

\(Z_2 = \frac{115 - 100}{15} = 1\)

Step 2 – Reading the table:

P(Z ≤ 1) = 0.8413

P(Z ≤ -1) = 0.1587

Step 3 – Subtract:

P(-1 < Z < 1) = 0.8413 - 0.1587 = 0.6826

Answer: approx. 68% of people have an IQ between 85 and 115

(This is the 68-95-99.7 rule!)

📋 Summary Table – Question Types

Question type Method
P(X < a) Compute Z, read from table
P(X > a) Compute Z, read from table, compute 1 − (table value)
P(a < X < b) Compute two Z-scores, look up both, subtract

📝 Summary

Raw score → Z-score → table → probability

"Greater than" = complementary percentage

"Between" = subtract areas